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Mathematics Forum
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| Author | Message / Information |
| Mr. Fox Quote | Reply | This message was updated on 3/1/2004 12:01:25 AM by Mr. Fox | A timely Middle East puzzle posted on: 2/29/2004 11:01:27 PM I don't know the solution to this puzzle. But my best guess is at the bottom. quote: I first made the assumption that the first step would be 10 equal trips to the same spot between the two cities. I further assumed that the pile left at that spot should be an even multiple of 1000kgs and that number should be 4000kgs. Okay, I made a lot of assumptions. This would require 9 round trips to that spot and one final drop. So if x equals the distance of the first leg then... 9(1000-2x)+(1000-x)=4000 x=~315.79 miles I then made the assumption that the second leg of the journey would then require 4 steps to leave exactly 1000kgs at the second stop. 3(1000-2x)+(1000-x)=1000 x=~428.57 miles Since the camel eats exactly 1 kg per mile, the amount left after the final leg would be. 315.79+428.57=744.36~kgs of grass Was I wrong? I'm new, so be gentle. |
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Robgirl
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A timely Middle East puzzle
replied on: 5/27/2005 6:08:21 AM So was Mr Fox right? I'm working on a solution..... |
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cramwit
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A timely Middle East puzzle
replied on: 10/28/2005 1:54:45 PM The smaller you make the back and forth pile-up sub trips the more efficient it is. using a one mile forth, drop, and back trip it takes .002 percent of the load per mile to feed the camel arriving at Damascus you have 1350 kgs of grass if you travel fractions of a mile this could probably be improved, but still won't be enough to pay for your back's medical bills from loading and unloading thousands of kg of grass every mile. |
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