Tired of seeing ads? Click here to upgrade to Elite Membership!


Mathematics Forum

Reply  New Topic New Poll Mathematics -> Statistics
Control Panel | search | Email to a Friend
Log In! | Register

Author Message / Information
butsee






Quote | Reply |


Random Number Problem
posted on: 12/9/2004 10:58:44 AM

I have a problem that I am trying to solve that I need some help with.

If you continue to pick numbers between 0 and 100 what is the theoretical average difference between two picks?

So you pick a random number between 0 and 100. Then you pick another random number (can be the same as the one you just pick), then pick another and another and another. What is the avergage difference between the numbers? Over time you should have an over all average difference between two concecuatively picked numbers.
balakrishnan_v




Quote | Reply |


Random Number Problem
replied on: 8/13/2005 12:45:31 PM

If you choose integers between 1 and 100
1,2..100
it is
33.33=3333/100

If you choose continuosly between 1 and 100,it is
323433/10000=32.3433
Kepler2006




Quote | Reply |


Random Number Problem
replied on: 7/25/2006 7:22:29 PM

Hi butsee

It is easier to do this with a set of cards numbered one to one hundred

If you are making a selection WITH replacement then the probably of picking one particular card out of 100 is 1/100
If as you say you replace the card and reshuffle thoroughly you are starting the same procedure all over again so the probability of picking one particular card is again 1/100 because each time you are repeating the same procedure however many times you do it. Each individual selection is independent and not influenced by the previous selection.

If you are NOT replacing the card after each selection your probability goes as follows
Initial selection 1/100
Second time 1/99
Third time 1/98
Forth time 1/97
And so on.

In both of the above cases the ‘average’ is determined by the number of times you make the selection.

Anthony Quinn
Euler




Quote | Reply |


Random Number Problem
replied on: 7/26/2006 1:11:18 AM

I believe they were asking for the average difference between values, not the average probability of a certain value. For example, Say you pick 46 and 87, these numbers have a difference of 41, and next you pick 32 and 56, which have a difference of 24. They are asking for the average difference between the two picked numbers should you continue the process over and over again, which would be in this particular case:

(41+24)/2=32.5
LinkBot





Gamers Wanted is looking for people to write game reviews and post news,
if your interested please visit Gamers Wanted About Us Page




 



Contact Administrator (must be logged in)


Tired of seeing ads? Click here to upgrade to Elite Membership!


ChatArea.com Help & News Forums | Terms of Use | Contact ChatArea.com | Advertising

Powered By ChatArea.com - Get your free Society today! © Copyright 2003 Wewp!