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Mathematics Forum
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| Author | Message / Information |
| Euler Quote | Reply | | A little help... posted on: 6/14/2006 5:20:28 PM Can anybody here help me write a program which would return all the values of x, for a given array (set) of values for y which satisfy the equation below: y=(pi)^x??? It would be greatly appreciated! |
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The Riemann Hypothesis
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A little help...
replied on: 6/17/2006 7:44:01 AM quote: So you have values of y and you need to find x? Shouldn't: int main(){ int I = 0; int yarray[n]; // Code to fill yarray with y values int xarray[n; Do{ xarray = ln(y) / ln(pi); I += 1; } while(x < n); return 0; } work? That assumes that there is one solution for y = pi^x though. I'm not sure if there is more than 1 solution. |
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Euler
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A little help...
replied on: 6/17/2006 10:30:20 PM Yes that would definitely work; however, I am not all that well versed in programming, so can I simply type ln and pi in the code and it will know what to do, and if so, is there some preprocessor directive I need to call? |
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The Riemann Hypothesis
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A little help...
replied on: 6/23/2006 6:52:46 AM #include <math.h> int main(){ int I = 0; int yarray[n]; const double pi = 3.141592654 // Code to fill yarray with y values yarray[0] = y value you want yarray[1] = another y value you want yarray[2] = ....etc int xarray[n]; Do{ xarray = log(y) / log(pi); I += 1; } while(x < n); return 0; } that c++ code will put it into the array xarray. Pi you have to define as a constant. Using #include <math.h> will allow you to use the log(n) command. log(n) is the natural logarithm of n. |
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Euler
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A little help...
replied on: 6/23/2006 7:07:03 PM Thank you very much, though I already figured it out for myself. Thanks again though! |
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