Mathematics.Calculus - ChatArea.com

Mathematics Forum

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Euler Quote \| Reply \|	Simple Challenge posted on: 6/29/2006 10:19:03 PM Here is a challenge involving simple vector calculus: Given the vector field F=[3xy^2]i+[4zy]j-[(2x+3z^3)]k, bounded by z=x^2+y+3 Find: Curl F at the point (1,3,7).
jehovah0121 Quote \| Reply \|	Simple Challenge replied on: 11/5/2006 11:31:02 PM My English level is quite limited. Please forgive me. Does Curl means the reverse trangle with a X on the right side? if so, I think Curl F is the determinant as follows (p is the symbol for partial differentiation) Curl F = det[i, j, k; p/px, p/py, p/pz; 3xy^2, 4zy, 2x+3z^3] = -4y i + 2 j - 6xy k When {x,y,z} = {1,3,7} the value will be -12i + 2j -18k. Is this right?
Euler Quote \| Reply \|	Simple Challenge replied on: 11/6/2006 10:58:46 PM That's correct! Good job!
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