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Mathematics Forum
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| noobie Quote | Reply | | Hi all i got some problems please help posted on: 7/27/2006 1:17:54 AM A page of a book are consecutive whole numbers, If you begin reading at the top of page x and stop at the bottom of page y, the number of pages you have read written as a formula is. The average of 5 numbers is 4, four of the numbers are 1,2,3,4 what is the other. In the multiplication P7## * 6 = #2#84 each # represents a unknown number. What is the value of P |
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No._ln_e
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Hi all i got some problems please help
replied on: 7/27/2006 3:55:09 AM 1. no. of pages=(y-x)+1 2. (1+2+3+4+x)/5=4 (10+x)/5=4 10+x=20 x=10 3.still processing... |
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Euler
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Hi all i got some problems please help
replied on: 7/27/2006 7:30:45 PM 3) If each # represents only a single digit, then this problem has no answer because in the multiplication: P7## x 6, ----- #2#84 there are only two values for # which would yield a 4 for the first step: 4 or 9. If #=4, then you would end up carrying a 2, and 6*4+2=26, which does not have the 8 in the ones digit necessary to match the 8 given in your answer. Similarly, if #=9, then 6*9+5=59, which does not have the necessary 8 either. |
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Euler
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Hi all i got some problems please help
replied on: 7/27/2006 7:40:02 PM 3) I should also mention that if you leave # as an unknown, single digit, then this problem is still impossible because: P7## x 6, ----- #2#84 means that 6*#=44, from the first multiplication step (which is impossible, as no whole number makes this statement true), in order for you to get 4 and have a 4 to carry in order to get the 8 that follows. Assuming that this is true, then you would be carrying a 4 again from the second step, which gives you 46, so the # must then be 6 (which is impossible as well, since 6*6 does not equal 44); however, assuming then that this is true too, then you would carry a 4 again, which means, from the final step, that 6*P+4=#2, so P=(#2-4)/6, and since it was previously determined that #=6, P=9.6667, which can not be true. |
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noobie
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Hi all i got some problems please help
replied on: 7/28/2006 1:09:05 AM i got p = 8, by trial and error though. |
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Euler
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Hi all i got some problems please help
replied on: 7/28/2006 8:04:28 PM Can you explain how 8 work, because I cannot make it work. Thanks! |
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prasannasagar_m
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Hi all i got some problems please help
replied on: 12/13/2006 7:00:13 AM Here is the explanation for the problem # 3. lets assume the equation to be P7xy4 * 6 = q2r84. When you multiply 6 with x in the number P7xy4, the maximum carry you can get from this multiplication is 5. So, when you multiply 7 with 6 and add the carry from the 100's digit multiplication i.e., x*6 we have a carry of 4(since 7*6 =42 and maximum carry is 5). when you multiply 6 with P and add previous carry we , it should be equal to q2. In other words, 6P+4 = q2. => 6P = 22 or 52 if P is an integer less than 10. => P = 3 or 8 depending on what r is. |
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