Mathematics.Calculus - ChatArea.com

Mathematics Forum

Author	Message / Information
Sirius_GTO Quote \| Reply \| This message was updated on 10/8/2006 6:14:41 AM by Sirius_GTO	derivative posted on: 10/8/2006 6:09:10 AM f(x)=2x^3-1/x^2 first I did this: I used the quotient rule to get: 1.x^2(2x^3-1) + 2x^3-1(x^2) 2.x^2(6x^2) + 2x^3-1(x^2) 3.6x^4 + 4x+4 -2x 4.2x(3x^3+2x^3-1)/x^4 and I arrived with my final answer: 2x(3x^3+2x+3-1)/x^4 I know I got it wrong. But I would love to know why and what I should have done instead. Thank you so much for your help!
Sirius_GTO Quote \| Reply \| This message was updated on 10/8/2006 6:21:21 AM by Sirius_GTO	derivative replied on: 10/8/2006 6:15:16 AM I just noticed... I used an addition when it should have been a subtraction...DOH! However I still think I did the problem wrong because this is what I got doing it with the negative sign. x^2(6x^2) - 2x^3-1(2x)/x^4 then i got: 6x^4-4x^4-2x/x^4
Sirius_GTO Quote \| Reply \|	derivative replied on: 10/8/2006 5:52:41 PM oops I solved it. Nub mistakes. Much love. Thanks everyone.
Grogler Quote \| Reply \|	derivative replied on: 11/8/2006 9:25:09 AM I don't believe it is so difficult. The answer is 6X^2+2/X^3
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