| Tired of seeing ads? Click here to upgrade to Elite Membership! |
Mathematics Forum
|
| Author | Message / Information |
| gamesmaniaz Quote | Reply | | Simutaneous DE posted on: 10/18/2006 6:57:55 AM How do you solve the simultaneous differential equation below? dx/dt=(2-x)y dy/dt=(y^2)/x When t=0, x=y=1 And do I need to use laplace transforms? |
|
herbert
Quote | Reply | |
Simutaneous DE
replied on: 10/19/2006 10:36:56 AM As far as I can see you only need to divide the two equations by each other in order to get dy/y = dx/(x*(2-x)) andt this problem can be solved easily by eypanding the fraction on the right side and I guess this to be equal to (1/x -1/(2-x))/2 forgive me if there is some minus wrong. Please check for it. Mathematiccs is easy. Only calculating is difficult.... Thus you arrive at dy/y = 0.5 (1/x - 1/(2-x))dx or dy/y = 0.5dx/x - 0.5dx/(2-x) which should be easy to solve including the required boundary conditions. with kind regards |
|
LinkBot
|
Gamers Wanted is looking for people to write game reviews and post news, |
|
|
| Tired of seeing ads? Click here to upgrade to Elite Membership! |
ChatArea.com Help & News Forums | Terms of Use | Contact ChatArea.com | Advertising
Powered By ChatArea.com - Get your free Society today! © Copyright 2003 Wewp!