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Mathematics Forum
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| Author | Message / Information |
| johnwarwick Quote | Reply | | Geometry Question posted on: 1/10/2007 9:19:05 PM My question is this. I cannot find a formula for the amount of total diagonals in a polygon based on the amount of sides it is. I have the following pattern. 3 sides no diagonals, 4 sides 2 diagonals, 5 sides 5 diagonals, 6 sides 9 diagonals, and 7 sides 14 diagonals. The formula would have to be n sides equals its diagonals. |
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herbert
Quote | Reply | |
Geometry Question
replied on: 1/11/2007 4:24:38 AM call the number of sides of the polygon n define : number of primary diagonals is the number of diagonals leading from ONE edge point to all the other edges of the polygon except lines which are SIDES off the polygon. call this number m the answer follows thus : the number of all possible diagonals is equal to the product of m x n divided by two example n m number of internal diagonals = mn/2 3 0 0 4 1 2 5 2 5 6 3 9 7 4 14 8 5 20 and so on I think the solution equation should be obvious |
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