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johnwarwick






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Geometry Question
posted on: 1/10/2007 9:19:05 PM

My question is this. I cannot find a formula for the amount of total diagonals in a polygon based on the amount of sides it is. I have the following pattern. 3 sides no diagonals, 4 sides 2 diagonals, 5 sides 5 diagonals, 6 sides 9 diagonals, and 7 sides 14 diagonals. The formula would have to be n sides equals its diagonals.
herbert




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Geometry Question
replied on: 1/11/2007 4:24:38 AM

call the number of sides of the polygon n

define : number of primary diagonals is the
number of diagonals leading from ONE edge
point to all the other edges of the polygon
except lines which are SIDES off the polygon.
call this number m

the answer follows thus : the number of all
possible diagonals is equal to the product
of m x n divided by two

example

n m number of internal diagonals
= mn/2
3 0 0
4 1 2
5 2 5
6 3 9
7 4 14
8 5 20

and so on
I think the solution equation should be obvious





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