Mathematics.Mathematical Jokes and Puzzles

Mathematics Forum

Author	Message / Information
jgreer Quote \| Reply \|	The Million Dollar Question posted on: 2/15/2007 1:46:24 AM This is not a homework assignment, just something I am having trouble figuring out and thought someone may be able to help. How many different combinations of six numbers are there using all of the numbers between 1 and 45? i.e. 1,2,3,4,5,6 - 1,2,3,4,5,7 - 1,2,3,4,5,45 - - - 40,41,42,43,44,45 I have tried to figure this out a few times but constantly get confused or think i have left some out. note: The combinations do not include those that already have the same numbers i.e. If you had 1,2,3,4,5,6 you would not need 6,5,4,3,2,1 as a combination as all six numbers are already counted as a combination. Please leave your answers to this problem if you choose to try to figure it out as it will be interesting to see what everyone comes up with. Cheers
mathgeek Quote \| Reply \|	The Million Dollar Question replied on: 3/15/2007 11:47:18 AM The answer is 45!/(6! * 39!) = 8,145,060
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