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cramwit






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Is a complete prime list as factors + 1 = prime?
posted on: 3/30/2007 7:36:39 AM

If you take the complete list of primes up to Pn [2,3,5,7,11,13, . . . ,Pn]
multiply them, then add one, is that a prime?
( 2 * 3 * 5 * 7 * 11 * 13 * ...* Pn ) + 1 = a prime?

You could calculate & check all the primes from Pn to sqrt(Product) for a pair of factors.
And since you have used all the smaller potential prime factors a set of 3 or more factors is almost impossible.

I am just wondering if anyone else thinks this might be true, & if there is a way of proving [or disproving] it?

If it is true, it would be a way of manufacturing [very] large prime numbers.

Also i was wondering if a pair of bounding primes are of any use determining the primes that lie between them?
cramwit




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Is a complete prime list as factors + 1 = prime?
replied on: 4/1/2007 8:54:08 AM

Oops.
I should have checked this before posting.
It fails at:
2 * 3 * 5 * 7 * 11 * 13 + 1 = 30031 = 59 * 509
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