Mathematics.Algebra - ChatArea.com

Mathematics Forum

Author	Message / Information
headache Quote \| Reply \|	Fractions with variables posted on: 9/23/2007 1:20:48 AM So I've been trying to solve for "x" for about 5 hours now... I keep on getting -6, but when I plug it back into the equation for "x" I see that it does not check out.. Can someone help? The equation that you must solve for "x" is: (x/12)-((x-3)/3)=(1/2) I realize that you have to make all of the denominators the same by finding the lowest common denominator and then adjust the numerators (on both sides)... But I suppose my mistake is made somewhere after that b/c I cannot seem to get the correct value of "x".
Kanpree Quote \| Reply \|	Fractions with variables replied on: 9/26/2007 4:53:41 PM Click on the link below: http://messenger.providesupport.com/messenger/stepsedu.html?ps_s=emaLHq4lr5dP&ps_mht=true Once you click on the link it will display Customer Support window. Just select the Technical Support Option, enter your name, write your Question and click on “Start Chat”. You will be connected to representative. He will connect you to the Tutor and tutor will help you for one hour absolutely free
cramwit Quote \| Reply \|	Fractions with variables replied on: 10/11/2007 4:51:12 PM (x/12)-((x-3)/3)=(1/2) (x/12)-(x/3 -3/3)=1/2 (x/12)-[(4x/12)-1]=1/2 (x-4x)/12 + 1 = 1/2 -3x/12 = -1/2 = -6/12 -3x = -6 3x = 6 x = 2
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